How much heat is evolved when 267 g of ammonia gas condenses to a liquid at its boiling point?
heat evolved = mass x heat vaporization.
To determine the amount of heat evolved during the condensation of ammonia gas, we need to use the equation
q = m × ΔHvap
where:
q is the heat evolved or absorbed (in Joules),
m is the mass of the substance (in grams), and
ΔHvap is the heat of vaporization (in J/g).
First, we need to find the mass of ammonia gas in grams. The problem gives us that the mass of ammonia gas is 267 g.
Next, we need to find the heat of vaporization of ammonia. The heat of vaporization is the amount of heat energy required to convert one gram of a substance from a liquid to a gas at its boiling point. For ammonia, the heat of vaporization is given as 23.35 J/g.
Now we can substitute the values into the equation:
q = 267 g × 23.35 J/g
Calculating this gives us:
q = 6233.45 J
Therefore, when 267 g of ammonia gas condenses to a liquid at its boiling point, approximately 6233.45 J of heat is evolved.