Find all real zeros of the function y= 3x+8
replace y with zero and solve
To find the real zeros of the function y = 3x + 8, we need to find the values of x that make y equal to zero.
For a linear function like this, the real zero occurs when the y-value is equal to zero. In this case, we need to solve the equation 3x + 8 = 0.
To solve for x, we can start by subtracting 8 from both sides of the equation. This gives us 3x = -8.
Next, we can divide both sides of the equation by 3 to isolate the x variable. The equation becomes x = -8/3.
So the only real zero of the function y = 3x + 8 is x = -8/3.