λ for one line of the hydrogen spectrum is .4118 x 10-4 cm. Use this value in the Rydberg equation to calculate the RH value using n1 = 2, and n2 = 5.
change the line spectrum to meters
you know the equation is Et= Ef-Ei (i think is the equation they want you to use, i don't know what they want),
well then that would be (-Rhc/nf^2)-(-Rhc/ni^2)
Rhc= 2.179 Z 10^-18 J/atom or
1312 kJ/mol
if this isnt the equation you needed sorry
This is a double post.
To calculate the RH value using the Rydberg equation, we will first convert the given wavelength to meters.
Given: λ = 0.4118 x 10^(-4) cm
To convert cm to meters, we need to multiply by a conversion factor:
1 cm = 0.01 meters
Therefore, λ = (0.4118 x 10^(-4)) * 0.01 = 4.118 x 10^(-6) meters.
Now, we can proceed with the Rydberg equation:
1/λ = RH * (1/n1^2 - 1/n2^2)
Substituting the values:
n1 = 2, n2 = 5, and λ = 4.118 x 10^(-6) meters.
We can rearrange the equation to solve for RH:
RH = 1/λ * (1/n1^2 - 1/n2^2)
RH = (1 / 4.118 x 10^(-6)) * (1/2^2 - 1/5^2)
RH = (1 / 4.118 x 10^(-6)) * (1/4 - 1/25)
RH = (1 / 4.118 x 10^(-6)) * (25/100 - 4/100)
RH = (1 / 4.118 x 10^(-6)) * (21/100)
RH = 2.563 x 10^(15) m^(-1)
Therefore, the RH value using n1 = 2 and n2 = 5 is approximately 2.563 x 10^(15) m^(-1).