what is the remainder when ka^3-3a^2+5a-8 is divided by a+1.
please help and thank you
To find the remainder when dividing the polynomial ka^3 - 3a^2 + 5a - 8 by a+1, we can use the Remainder Theorem.
The Remainder Theorem states that if you divide a polynomial f(x) by x - a, the remainder is equal to f(a). In this case, we want to divide the polynomial by a+1, so we need to find the remainder when a = -1.
To find the remainder, substitute -1 for the variable 'a' in the polynomial and simplify:
R = k(-1)^3 - 3(-1)^2 + 5(-1) - 8
R = -k - 3 - 5 - 8
R = -k - 16
Therefore, the remainder when dividing ka^3 - 3a^2 + 5a - 8 by a+1 is -k - 16.