Hockey teams recueve 2 points when they win and 1 point when they tie. One season, a team won a championship with 66 points. They won 12 more games than they tied. How many winds dd the team have and how many ties?

Let W = games won and T = games tied.

W = T + 12

2W + T = 66

Substitute T + 12 for W in the second equation and solve for T. Put that value in the second equation to find W. To check, put both values into the second equation.

To solve this problem, let's first assume that the team won x games and tied y games.

According to the given information, each win earns 2 points and each tie earns 1 point. Since the team won 12 more games than it tied, we can write the equation:

x = y + 12

Now let's calculate the total number of points earned by the team. We know that the team won 66 points in total. Since each win is worth 2 points and each tie is worth 1 point:

2x + 1y = 66

Now we can substitute the value of x from the first equation into the second equation:

2(y + 12) + y = 66

Simplifying this equation will give us:

2y + 24 + y = 66

Combining like terms:

3y + 24 = 66

Subtracting 24 from both sides of the equation:

3y = 42

Dividing both sides by 3:

y = 14

Now that we know y, we can substitute it back into the first equation to find x:

x = 14 + 12
x = 26

So the team won 26 games and tied 14 games.