A typical fat in the body is glyceral trioleate, C57H104O6. When it is metabolized in the body, it combines with oxygen to produce carbon dioxide, water, and 3.022 x 10^4 kJ of heat per mole of fat.
B)How many kilokoules of energy must be evolved in the form of heat if you want to get rid of five pounds of this fat by combustion?
In part A) i was asked to write a balanced equation.
It is: C57H104O6(S) + 80(O2)(G)--> 57CO2(G) + 52H20
what do i do?
I would convert 5 pounds to grams, then convert to moles of fat.
The reaction gives you 3.022 x 10^4 kJ/1 mol. Go from there.
To determine the amount of energy evolved in the form of heat when five pounds (lbs) of glyceral trioleate is combusted, you can follow these steps:
1. Convert the weight of the fat from pounds to grams. Since 1 pound is approximately equal to 453.592 grams, five pounds is equal to 2267.96 grams.
2. Calculate the molar mass of glyceral trioleate (C57H104O6). This can be done by summing the atomic masses of each element in the chemical formula. The molar mass is found to be approximately 885.51 grams/mole.
3. Determine the number of moles of fat. Divide the mass of the fat (in grams) by the molar mass of glyceral trioleate. In this case, 2267.96 grams divided by 885.51 grams/mole gives approximately 2.56 moles of fat.
4. Use the given information that 3.022 x 10^4 kJ of heat is produced per mole of fat metabolized. Multiply this value by the number of moles of fat calculated in step 3 to obtain the total energy evolved in kilojoules (kJ). In this case, (3.022 x 10^4 kJ/mol) x 2.56 mol gives approximately 7.74 x 10^4 kJ.
Therefore, the amount of energy evolved in the form of heat when five pounds of glyceral trioleate is combusted is approximately 7.74 x 10^4 kilojoules (kJ).
To determine how many kilojoules of energy must be evolved in the form of heat when five pounds of glyceral trioleate is combusted, we can follow these steps:
1. Convert the given mass of fat from pounds to grams.
- 5 pounds = 5 lbs * 453.592 g/lb = 2267.96 g
2. Calculate the number of moles of glyceral trioleate in the given mass.
- To do this, we need to know the molar mass of glyceral trioleate (C57H104O6):
Molar mass of C57H104O6 = (57 * atomic mass of C) + (104 * atomic mass of H) + (6 * atomic mass of O)
= (57 * 12.01 g/mol) + (104 * 1.01 g/mol) + (6 * 16.00 g/mol)
= 874.87 g/mol
- Moles of glyceral trioleate = mass / molar mass
= 2267.96 g / 874.87 g/mol
≈ 2.59 moles
3. Use the balanced equation from part A to find the energy evolved per mole of fat.
- From the balanced equation, we know that for every mole of glyceral trioleate (C57H104O6) combusted, it produces 3.022 x 10^4 kJ of heat.
4. Calculate the total energy evolved when 2.59 moles of glyceral trioleate are combusted.
- Energy evolved = number of moles * energy evolved per mole
= 2.59 moles * 3.022 x 10^4 kJ
≈ 7.817 x 10^4 kJ
Therefore, approximately 7.817 x 10^4 kilojoules of energy must be evolved in the form of heat if you want to get rid of five pounds of glyceral trioleate by combustion.