Find the vertex of the parabola given by f(x) = x^2 - 3x + 4
My answer was (3,13). Am I correct?
f(x)=x^2-3x+9/4 + 4-9/4
= (x-3/2)^2 + 7/4
looks like the vertex is at x=3/2, y= you compute it.
My answer was (3,13). Am I correct?
= (x-3/2)^2 + 7/4
looks like the vertex is at x=3/2, y= you compute it.