Suppose h(x) = 3x and k(x) = log3(x). What is k(h(x))? What about h(k(x))? Start with a few numbers to convince yourself. Explain completely why this is true.

oops already did that one

i just need to know how to do this other problem.
Since a logarithm is the interchange (or inverse) of an exponential function, each logarithmic function has a particular base. Note that we write the base below the line (like a subscript). For example, we write log2(x). This looks a bit confusing, since the "x " is above the 2. It almost looks like 2x, but it isn't. When you write it, make it very clear. Most log equations can be written as an exponential equation and vice versa, as you saw in the previous problem. Copy each equation shown below. Then rewrite each equation in the other form.

a) y = 5x

b) y = log7(x)

c) 8x = y

d) AK = C

e) K = logA(C)

f) log (k)=N
1/2

so i tried a and i got

log ^(y)=x
5
Correct?

I think you might mean

y = 5^x power
then
log5 (y) = x log5 (5) but log5 (5) = 1
log5 (y) = x
-------------------------
y = log7 (x)

7^y = 7^[log7(x)] but base^[logbase(x)]=x
7^y = x

To find k(h(x)), we need to substitute h(x) into the function k(x).

Let's start with a specific value for x, such as x = 2.

Step 1: Find h(x)
h(2) = 3(2) = 6

Step 2: Substitute h(x) into k(x)
k(h(x)) = k(6)

Now, we need to evaluate k(6) by substituting 6 into the function k(x).

k(6) = log3(6)

To compute this, we need to determine what power of 3 gives us 6. In other words, we need to solve the equation 3^y = 6.

Taking the logarithm of both sides, we get:

y = log3(6)

Therefore, k(6) = log3(6) = y, where y is the solution to 3^y = 6.

Now, let's find h(k(x)).

Using the same process, we need to substitute k(x) into the function h(x).

Step 1: Find k(x)
For example, let's pick x = 9.

k(9) = log3(9)

Here, we need to determine what power of 3 gives us 9. In other words, we need to solve the equation 3^y = 9.

Taking the logarithm of both sides, we get:

y = log3(9)

Step 2: Substitute k(x) into h(x)
h(k(x)) = h(log3(x))

Now, we substitute k(x) = log3(x) into h(x).

h(log3(x)) = 3(log3(x))

Again, substituting the value of x = 9, we have:

h(log3(9)) = 3(log3(9))

To evaluate this expression, we need to determine the value of log3(9) and compute the result.

By following the same process explained earlier, we find that log3(9) = 2.

Finally, we can calculate h(log3(9)):

h(log3(9)) = 3(2) = 6

Therefore, h(k(x)) = 6.

In summary, k(h(x)) = log3(6) and h(k(x)) = 6.