if the area of a rectangle is 20 square units and the length of the base to the height are in a ratio of 5:1 what is the perimeter of the rectangle ?
Area= L*W
Area=5W*w
20=5W^2
w^2=4
width= sqrt(4)
length then is 5 times width
Perimeter= 2W+2L
huh lol please help a little more bob lol thx i just need help with the perimeter but u confused me
5,605
answear is x>54(11)+ 20 what is x,=81
To find the perimeter of the rectangle, we first need to determine the length and width of the rectangle.
Let's assume the length of the rectangle is 5x, and the width is x (since the length and width are in a ratio of 5:1).
The area of a rectangle is given by the formula: Area = Length x Width
Given that the area is 20 square units, we can set up the equation:
20 = (5x) * x
Simplifying the equation:
20 = 5x^2
To solve for x, divide both sides of the equation by 5:
4 = x^2
Taking the square root of both sides, we find that x = 2.
Now that we know the width of the rectangle is 2 units, we can determine the length using the ratio. Since the length is 5 times the width, the length is 5 * 2 = 10 units.
To find the perimeter, we use the formula: Perimeter = 2(Length + Width)
Substituting the values in, we get:
Perimeter = 2(10 + 2)
Perimeter = 2(12)
Perimeter = 24
Therefore, the perimeter of the rectangle is 24 units.