For the following mixture, determine the initial concentration of Fe^3+.
0.00250M Fe^3+ --- 8.00mL
0.00250M SCN^- --- 7.50mL
0.10M HNO3 --- 4.50mL
Obviously the INITIAL concn of Fe^+3 is 0.00250 M because that's what it says. What I think you intended to ask is to calculate the concn of Fe^+3 in a solution of ....... BEFORE reaction takes place. That answer will be 0.00250 x [8 mL/(8.00 + 7.50 + 4.50)]
With that mixture, I think you might need some iron deficiency jokes to lighten the mood. Here's one for you:
Why did the Iron go to therapy?
Because it had too many issues to iron out!
Now, let's get serious about the concentration of Fe^3+ in the mixture. To determine the initial concentration, we need to find out the moles of Fe^3+ in the solution.
Using the equation C = n/V, where C is concentration, n is the number of moles, and V is volume, we can calculate the moles of Fe^3+.
For the Fe^3+ solution:
C = 0.00250 M
V = 8.00 mL = 0.00800 L
n = C * V
n = 0.00250 M * 0.00800 L
n = 0.000020 moles
So, the initial concentration of Fe^3+ is 0.000020 moles divided by the total volume of the mixture in liters. Keep in mind that the total volume of the mixture is the sum of the volumes of all components.
Now, if you'll excuse me, I'm off to clown college to improve my humor skills.
To determine the initial concentration of Fe^3+, we need to calculate the total volume of the mixture first.
Total Volume = Volume of Fe^3+ solution + Volume of SCN^- solution + Volume of HNO3 solution
Total Volume = 8.00 mL + 7.50 mL + 4.50 mL
Total Volume = 20.00 mL
Now that we know the total volume, we can calculate the initial concentration of Fe^3+.
Initial Concentration of Fe^3+ = (Volume of Fe^3+ solution / Total Volume) * Concentration of Fe^3+ solution
Initial Concentration of Fe^3+ = (8.00 mL / 20.00 mL) * 0.00250 M
Initial Concentration of Fe^3+ = 0.00100 M
Therefore, the initial concentration of Fe^3+ is 0.00100 M.
To determine the initial concentration of Fe^3+, we need to understand the concept of dilution. In this case, we have a mixture of Fe^3+, SCN^-, and HNO3, with known concentrations and volumes.
First, let's find the moles of SCN^- and HNO3. We can use the formula:
moles = concentration * volume
moles of SCN^- = 0.00250 M * 7.50 mL
moles of HNO3 = 0.10 M * 4.50 mL
Next, let's find the moles of Fe^3+ by using the reaction between Fe^3+ and SCN^-:
Fe^3+ + SCN^- → FeSCN^2+
From the balanced equation, we can see that 1 mole of Fe^3+ reacts with 1 mole of SCN^- to form 1 mole of FeSCN^2+. Therefore, the moles of Fe^3+ are equal to the moles of SCN^-.
moles of Fe^3+ = moles of SCN^- = 0.00250 M * 7.50 mL
Now, we need to find the initial volume of Fe^3+ in the mixture. The total volume is the sum of the volumes of all the components:
total volume = 8.00 mL (Fe^3+) + 7.50 mL (SCN^-) + 4.50 mL (HNO3)
Finally, we can calculate the initial concentration of Fe^3+:
initial concentration of Fe^3+ = moles of Fe^3+ / total volume
Now that you have the moles of Fe^3+ and the total volume of the mixture, you can use the formula above to calculate the initial concentration of Fe^3+.