Determine the molarity of FD&C Yellow #5 in the following solution that's prepared by mixing the dye solution with water and alcohol. None of the solutes react with one another.
6.35x10^-5M FD&C Yellow #5 = 6.50mL
deionized water = 6.50mL
ethyl alcohol = 6.80mL
6.35 X10^-5 M x [(6.80/total volume)]
I see total volume as 6.50 + 6.50 + 6.80 = ??
To determine the molarity of FD&C Yellow #5 in the solution, we need to know the total volume of the solution first. In this case, we can add the volumes of the dye solution, deionized water, and ethyl alcohol to find the total volume.
Total volume = volume of dye solution + volume of deionized water + volume of ethyl alcohol
= 6.50 mL + 6.50 mL + 6.80 mL
= 19.80 mL
Now that we have the total volume of the solution, we can calculate the molarity of FD&C Yellow #5 using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's convert the volume of the solution from milliliters to liters:
Volume of solution = 19.80 mL / 1000
= 0.01980 L
Now, we need to calculate the moles of FD&C Yellow #5. We can use the molarity and volume of the dye solution provided:
Moles of FD&C Yellow #5 = Molarity × Volume (in liters)
= 6.35 × 10^-5 M × 6.50 mL / 1000
= 4.12 × 10^-7 moles
Finally, we can calculate the molarity of FD&C Yellow #5:
Molarity (M) = Moles of solute / Volume of solution
= 4.12 × 10^-7 moles / 0.01980 L
= 2.08 × 10^-5 M
Therefore, the molarity of FD&C Yellow #5 in the solution is 2.08 × 10^-5 M.