Question:
The table below shows the drinking habits of adult men and women.
Men Women Total
Non-Drinker 387 421 808
Occasional Drinker 45 46 91
Regular Drinker 90 69 159
Heavy Drinker 37 34 71
Total 559 570 1129
If one of the 1,129 people is randomly chosen, what is the probability that the person is a man or a heavy drinker? Round your answer to 3 decimal places.
My answer:
P(man or a heavy drinker) = P(man) + P(heavy drinker)
= (559/1129) + (37/1129)
= 596/1129
= .528
Do you want to include those that are both heavy drinkers and men in your either-or answer?
(559/1129) + (37/1129) - (90/1129) = ?
I hope this helps.
(559/1129) + (37/1129) - (90/1129) = ?
To find the probability that a randomly chosen person is either a man or a heavy drinker, you need to calculate the sum of the probabilities of being a man and being a heavy drinker separately.
First, find the probability of being a man. From the table, you can see that there are 559 men out of 1129 people in total. So the probability of being a man is 559/1129.
Next, find the probability of being a heavy drinker. From the table, you can see that there are 71 heavy drinkers out of 1129 people in total. So the probability of being a heavy drinker is 71/1129.
Now, add these two probabilities together to find the probability of being either a man or a heavy drinker:
P(man or a heavy drinker) = P(man) + P(heavy drinker)
= (559/1129) + (71/1129)
= 630/1129
Finally, round your answer to three decimal places:
P(man or a heavy drinker) ≈ 0.557