Question:
The table below shows the drinking habits of adult men and women.
Men Women Total
Non-Drinker 387 421 808
Occasional Drinker 45 46 91
Regular Drinker 90 69 159
Heavy Drinker 37 34 71
Total 559 570 1,129
If one of the 1,129 people is randomly chosen, what is the probability that the person is a regular drinker or heavy drinker? Round your answer to 3 decimal places.
My answer:
P(regular drinker or heavy drinker) = P(regular drinker) + P(heavy drinker)
= (159/1129) + (71/1129)
= 230/1129
= .204
I agree
To calculate the probability that the randomly chosen person is a regular drinker or heavy drinker, you first need to determine the number of regular drinkers and heavy drinkers separately.
From the table, you can see that there are 159 regular drinkers and 71 heavy drinkers.
Now, divide the sum of regular drinkers and heavy drinkers by the total number of people in the sample:
P(regular drinker or heavy drinker) = (159 + 71) / 1129.
Calculate the numerator:
159 + 71 = 230.
Therefore, the probability that the person is a regular drinker or heavy drinker is:
P(regular drinker or heavy drinker) = 230 / 1129.
To round the answer to three decimal places, calculate the result:
P(regular drinker or heavy drinker) ≈ 0.204.