Given this reaction:
Pb(NO3)2 + 2 KCl --> PbCl2 + 2KNO
a. How many milliliters of 2.00 M Pb(NO3)2 will react with 50.0 mL of 1.50 M KCl
Moles KCl = M x L.
Using the coefficients in the balanced equation, convert moles KCl to moles Pb(NO3)2.
Then moles Pb(NO3)2 = M x L and solve for L (then convert to mL).
Still not understanding on how to set up the problem to get the answer.
Sorry but i figured it out.
To find out how many milliliters of 2.00 M Pb(NO3)2 will react with 50.0 mL of 1.50 M KCl, we can use the concept of stoichiometry.
First, let's write out the balanced chemical equation:
Pb(NO3)2 + 2 KCl → PbCl2 + 2 KNO3
From the equation, we can see that 1 mole of Pb(NO3)2 reacts with 2 moles of KCl.
Step 1: Convert the given volume of KCl to moles.
To do this, we'll use the molarity (M) and volume (V) information for KCl.
Molarity (M) = moles/volume (L)
Given:
Molarity of KCl (MKCl) = 1.50 M
Volume of KCl (VKCl) = 50.0 mL = 0.0500 L
Using the formula:
moles of KCl = MKCl * VKCl
moles of KCl = 1.50 M * 0.0500 L
Step 2: Determine the moles of Pb(NO3)2 needed.
Since the stoichiometry of the reaction is 1:2 (Pb(NO3)2:KCl), we can say that 1 mole of Pb(NO3)2 reacts with 2 moles of KCl.
moles of Pb(NO3)2 needed = (moles of KCl) / 2
Step 3: Convert the moles of Pb(NO3)2 to volume (mL).
Now, we'll use the molarity and volume information for Pb(NO3)2 to calculate the volume needed.
Given:
Molarity of Pb(NO3)2 (MPb(NO3)2) = 2.00 M
To find the volume (VPb(NO3)2) required for a given number of moles (moles of Pb(NO3)2 needed), we can use:
VPb(NO3)2 = (moles of Pb(NO3)2 needed) / (MPb(NO3)2)
Substituting the values from the previous steps, we get:
VPb(NO3)2 = (moles of KCl / 2) / (MPb(NO3)2)
VPb(NO3)2 = (moles of KCl / 2) / (2.00 M)
Finally, we can calculate the value:
VPb(NO3)2 = (moles of KCl / 4.00)
Step 4: Calculate the volume in mL.
The result from step 3 gives us the volume in liters. To convert it to milliliters, we use the conversion factor:
1 L = 1000 mL
So, the final answer would be:
Volume of Pb(NO3)2 = (moles of KCl / 4.00) * 1000 mL
Now you can substitute the value of "moles of KCl" that you calculated in step 1 into the equation to find the volume of Pb(NO3)2 that will react with 50.0 mL of 1.50 M KCl.