i need to find the amount of gallons of different water heights on a Horizontal tank with Elliptical Cross-Sections
minor axis height is 4
minor axis length is 6
tank length is 16
Duplicate post, already answered.
I gave you the formula for the total volume. If you want the volume at different heights, you have to say which level heights you want. That is where the need for calculus comes in.
You must have mistyped something. You can't have two minor axes.
To find the amount of gallons for different water heights in a Horizontal tank with Elliptical Cross-Sections, you can use the formula for the volume of an elliptical cylinder.
The formula for the volume (V) of an elliptical cylinder is given by:
V = π * (minor axis length/2)^2 * (minor axis height) * (water height)
In this case, the minor axis length is 6, the minor axis height is 4, and the tank length is 16.
To find the volume for a specific water height, plug in the values into the formula:
V = π * (6/2)^2 * 4 * (water height)
Once you have the volume, you can convert it to gallons by multiplying it by a conversion factor. Since 1 gallon is approximately equal to 0.13368 cubic feet, you can use this conversion factor to convert the volume from cubic units to gallons.
Let's say you want to find the volume for a water height of 8 inches:
V = π * (6/2)^2 * 4 * 8
V ≈ 3.14 * 3^2 * 4 * 8
V ≈ 3.14 * 9 * 4 * 8
V ≈ 3.14 * 36 * 8
V ≈ 904.32 cubic inches
To convert the volume to gallons:
V in gallons = 904.32 * 0.13368
V in gallons ≈ 120.96 gallons
So, for a water height of 8 inches, the tank would hold approximately 120.96 gallons.