Classify each reaction and balance the equations.

Al(OH)3 ==> Al2O3 + H2O

To classify and balance the given reaction equation, let's break it down step by step:

Step 1: Identify the reactants and products.
- Reactant: Al(OH)3 (aluminum hydroxide)
- Products: Al2O3 (aluminum oxide) and H2O (water)

Step 2: Determine the type of reaction.
In this case, it is a decomposition reaction. Decomposition reactions occur when a compound breaks down into simpler substances.

Step 3: Write the balanced equation.
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Al(OH)3 → Al2O3 + H2O

Let's balance the equation by following these steps:

1. Balance the aluminum (Al) atoms:
2 Al(OH)3 → Al2O3 + H2O

2. Balance the hydrogen (H) atoms:
2 Al(OH)3 → Al2O3 + 3 H2O

3. Balance the oxygen (O) atoms:
2 Al(OH)3 → Al2O3 + 3 H2O

Now the equation is balanced as follows:

2 Al(OH)3 → Al2O3 + 3 H2O

In conclusion, the reaction can be classified as a decomposition reaction, and the balanced equation is:

2 Al(OH)3 → Al2O3 + 3 H2O

The given chemical equation is:

Al(OH)3 ==> Al2O3 + H2O

To balance this equation, we need to make sure that there are an equal number of each type of atom on both sides of the equation.

First, let's look at the aluminum (Al) atoms. On the left side, we have 1 Al atom, while on the right side, we have 2 Al atoms. To balance the Al atoms, we can put a coefficient of 2 in front of Al(OH)3:

2Al(OH)3 ==> Al2O3 + H2O

Now, let's look at the oxygen (O) atoms. On the left side, we have 9 O atoms (3 from each OH group), while on the right side, we have 3 O atoms in Al2O3 and 1 O atom in H2O. To balance the O atoms, we can put a coefficient of 3 in front of H2O:

2Al(OH)3 ==> Al2O3 + 3H2O

Finally, let's look at the hydrogen (H) atoms. On the left side, we have 6 H atoms (2 from each OH group), while on the right side, we have 6 H atoms in the 3 H2O molecules. The hydrogen atoms are already balanced.

The balanced chemical equation is:

2Al(OH)3 ==> Al2O3 + 3H2O

Now, let's classify this reaction. This is a decomposition reaction, as a single compound (Al(OH)3) is breaking down into multiple products (Al2O3 and H2O).

Surely you don't need help balancing this decomposition reaction.