a scientist wants to make a solution of tribasic sodium phosphate ,Na3PO4, for an experiment. how many grams of Na3PO4 will be needed to produce 750 mL of a solution that has a concentration of Na+ ions of 1.30M

The easiest way is to solve for grams Na3PO4 needed, then divide by 3 since there are 3 moles Na^+ per mole Na3PO4.

M = moles/L
1.3 M = moles/0.750 L
moles = 1.3 x 0.750 = ??
??/3 = moles Na3PO4 L needed for 1.3 M in Na^+.
Then moles = grams/molar mass.
You have moles and molar mass. Calcualte grams.

An experiment in your laboratory requires 500 mL of a .0200 M solution of Na2CO3. You are given solid Na2CO3, distilled water and a 500 mL volumetric flask Describe how to prepare the required solution showing all calculations and describing each step appropriately.

To calculate the amount of grams of Na3PO4 needed to prepare the solution, we need to start by understanding the concept of molarity and the formula of Na3PO4.

The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, we know the molarity of Na+ ions in the solution is 1.30M.

To find the number of moles of Na+ ions needed for the solution, we can set up the following equation:

Moles of Na+ ions = molarity × volume (in liters)

The volume given is 750 mL, which needs to be converted to liters by dividing by 1000:

Volume (in liters) = 750 mL ÷ 1000 = 0.75 L

Substituting the values, we have:

Moles of Na+ ions = 1.30 M × 0.75 L

To calculate the moles of Na3PO4 needed, we need to consider the ratio of Na+ ions to Na3PO4 molecules. From the formula of Na3PO4, we can see that there are three Na+ ions for every Na3PO4 molecule.

Therefore, the moles of Na3PO4 needed can be calculated as:

Moles of Na3PO4 = Moles of Na+ ions ÷ 3

Now, to find the grams of Na3PO4 needed, we need to use the molar mass of Na3PO4. The molar mass is the sum of the atomic masses of its constituent elements.

The atomic masses are:
Na = 22.99 g/mol
P = 30.97 g/mol
O = 16.00 g/mol

Molar mass of Na3PO4 = (3 × Na) + P + (4 × O)

Substituting the values and calculating, we have:

Molar mass of Na3PO4 = (3 × 22.99) + 30.97 + (4 × 16.00)

Finally, to find the grams of Na3PO4 needed, we can use the following equation:

Grams of Na3PO4 = Moles of Na3PO4 × Molar mass of Na3PO4

By substituting the calculated moles of Na3PO4 and the molar mass, we can find the final answer for the grams of Na3PO4 needed to prepare the solution.