According to the following reaction, how many moles of hydrogen iodide will

be formed upon the complete reaction of 30.0 grams of hydrogen gas with excess
iodine?

hydrogen (g) + iodine (s) hydrogen iodide (g)

moles hydrogen iodide

See the other post on limiting reaction. Be certain to change the 30g to moles.

24.99

To determine the number of moles of hydrogen iodide formed, we need to use the molar mass of hydrogen gas and the balanced chemical equation.

The molar mass of hydrogen gas (H2) is approximately 2.02 g/mol.

The balanced chemical equation shows that 1 mole of hydrogen gas reacts with 1 mole of iodine to form 2 moles of hydrogen iodide.

Therefore, we can calculate the number of moles of hydrogen iodide using the given mass of hydrogen gas:

moles of H2 = mass of H2 / molar mass of H2
= 30.0 g / 2.02 g/mol
= 14.85 mol

Since 1 mole of hydrogen gas reacts with 2 moles of hydrogen iodide, we can conclude that 14.85 moles of hydrogen gas will react to form twice as many moles of hydrogen iodide:

moles of hydrogen iodide = 2 × moles of H2
= 2 × 14.85 mol
= 29.70 mol

Therefore, 29.70 moles of hydrogen iodide will be formed upon the complete reaction of 30.0 grams of hydrogen gas with excess iodine.

To determine the number of moles of hydrogen iodide formed, you need to use the given mass of hydrogen gas and the stoichiometry of the reaction.

The balanced equation for the reaction is:

2H2(g) + I2(s) -> 2HI(g)

From the equation, you can see that 2 moles of hydrogen gas react to produce 2 moles of hydrogen iodide. This means the molar ratio between hydrogen gas and hydrogen iodide is 2:2 or 1:1.

First, convert the mass of hydrogen gas to moles using its molar mass. The molar mass of hydrogen gas (H2) is 2 g/mol.

30.0 g H2 * (1 mol H2 / 2 g H2) = 15.0 mol H2

Therefore, 30.0 grams of hydrogen gas is equal to 15.0 moles of hydrogen gas.

Since the molar ratio between hydrogen gas and hydrogen iodide is 1:1, the number of moles of hydrogen iodide formed will also be 15.0 moles.