1.A woman rides a carnival Ferris wheel at radius 15 m, completing five turns about its horizontal axis every minute. What are (a) the period of the motion, the (b) magnitude and (c) direction of her centripetal acceleration at the highest point, and the (d) magnitude and (e) direction of her centripetal acceleration at the lowest point?

2.The pilot of an aircraft flies due east relative to the ground in a wind blowing 20 km/h toward the south. If the speed of the aircraft in the absence of wind is 70km/h, what is the speed of the aircraft relative to the ground?

What is confusing?

I have the formula's to solving these two, but some information is missing...

To solve both of these problems, you'll need to use some basic physics formulas related to circular motion and vectors. Let's break it down step by step:

1. The Period of the Motion:
The period of the motion refers to the time it takes for one complete rotation. In this case, the woman completes five turns every minute. To find the period, you can use the formula:
Period (T) = 1 / Frequency (f)
Since the woman completes five turns per minute, the frequency is 5 Hz (1 Hz = 1 rotation per second).

2. The Magnitude and Direction of Centripetal Acceleration at the Highest Point:
Centripetal acceleration is the acceleration directed toward the center of the circular path. At the highest point of the Ferris wheel, the direction of centripetal acceleration is directed downward and its magnitude can be determined using the formula:
Centripetal Acceleration (a) = (Velocity (v))^2 / Radius (r)
To find the velocity, you need to know the circumference of the Ferris wheel (2πr) and divide it by the period (T). So the formula for velocity is:
Velocity (v) = 2πr / T
Now you can substitute the values into the centripetal acceleration formula to find its magnitude and direction.

3. The Magnitude and Direction of Centripetal Acceleration at the Lowest Point:
At the lowest point of the Ferris wheel, the direction of centripetal acceleration is directed upward. You can use the same formulas to find its magnitude and direction, but remember to adjust the velocity formula to reflect the different radius and period.

4. Speed of the Aircraft Relative to the Ground:
To find the speed of the aircraft relative to the ground, you need to consider the vectors involved. The aircraft is flying due east relative to the ground, while the wind is blowing toward the south. Since these vectors are at right angles, you can use the Pythagorean theorem to find the resultant vector, which represents the speed of the aircraft relative to the ground.

I hope this breakdown helps clarify how to approach these problems! Let me know if you have any further questions.