m= 5/6, (8,-9) find the equation of the line having the given slope and containing the given point
y = (5/6)x + b
-9 = (5/6)*8 + b
b = -54/6 - 40/6 = -94/6 = -15 2/3
y = 5x/6 - 15 2/3
the answer is
y = 5/6x - 9
Try fitting Lmay's answer to the data point (8, -9)
[(5/6)*8] -9 is not -9
To find the equation of a line given the slope and a point on the line, we can use the point-slope form of the equation.
The point-slope form of a linear equation is: y - y₁ = m(x - x₁), where m is the slope, (x₁, y₁) is a point on the line, and (x, y) are the coordinates of any other point on the line.
In this case, the slope (m) is given as 5/6 and the point (8, -9) is on the line.
Substituting the values into the point-slope form, we have:
y - (-9) = (5/6)(x - 8)
Simplifying the equation:
y + 9 = (5/6)(x - 8)
Next, we can multiply both sides of the equation by 6 to eliminate the fraction:
6(y + 9) = 5(x - 8)
Expanding both sides:
6y + 54 = 5x - 40
Rearranging the equation to the standard form (y = mx + b):
5x - 6y = 94
So, the equation of the line with a slope of 5/6 and passing through the point (8, -9) is 5x - 6y = 94.