from the equation : c3h8+5O2=3CO2+4H20
HOW MANY GRAMS OF H2O CAN BE PRODUCED FROM THE REACTION OF 8.5X10^22 MOLECULES PROPANE GAS, C3H8
Rewrite the equation in standard form.
C3H8 + 5O2 ==> 3CO2 + 4H2O.
2. Convert 8.5 x 10^22 molecules propane into moles. Remember 1 mole contains 6.02 x 10^23 molecules.
3. Using the coefficients in the balanced equation, convert moles propane to moles H2O.
4. Convert mols H2O to grams. g = moles x molar mass.
14.6 g H2O
To determine the number of grams of water (H2O) produced from the reaction of 8.5x10^22 molecules of propane gas (C3H8), we need to use stoichiometry.
The balanced equation provides the molar ratio between propane (C3H8) and water (H2O), which is 4:4. This means that for every 1 mole of propane, 4 moles of water are produced.
To find the number of moles of propane (C3H8) in 8.5x10^22 molecules, we can use Avogadro's number. Avogadro's number states that 1 mole of any substance contains 6.022x10^23 particles.
Number of moles of C3H8 = Number of molecules / Avogadro's number
= 8.5x10^22 / 6.022x10^23
= 0.141 mole
Now, using the stoichiometric ratio from the balanced equation, we can determine the number of moles of water (H2O) produced.
Number of moles of H2O = Number of moles of C3H8 x (4 moles H2O / 1 mole C3H8)
= 0.141 mole x 4
= 0.564 mole
Finally, we can calculate the mass of water (H2O) produced using the molar mass of water, which is 18.015 g/mol.
Mass of H2O = Number of moles of H2O x molar mass of H2O
= 0.564 mole x 18.015 g/mol
= 10.14 grams
Therefore, 10.14 grams of water (H2O) can be produced from the reaction of 8.5x10^22 molecules of propane gas (C3H8).
To find out how many grams of H2O can be produced from the reaction of 8.5x10^22 molecules of propane gas (C3H8), we will follow these steps:
Step 1: Calculate the molar mass of C3H8 (propane).
The molar mass of carbon (C) is 12 g/mol, and the molar mass of hydrogen (H) is 1 g/mol. Since there are three carbon atoms and eight hydrogen atoms in propane, the molar mass of C3H8 is:
Molar mass of C3H8 = (3 * 12 g/mol) + (8 * 1 g/mol) = 36 g/mol + 8 g/mol = 44 g/mol.
Step 2: Find the mole ratio between C3H8 and H2O.
From the balanced equation: C3H8 + 5O2 → 3CO2 + 4H2O, we can see that for every 1 mole of C3H8, 4 moles of H2O are produced.
Step 3: Convert the number of propane molecules to moles.
Since 1 mole of any substance contains 6.022x10^23 molecules (Avogadro's number), we can use this conversion factor to convert the number of propane molecules to moles.
Moles of C3H8 = (8.5x10^22 propane molecules) / (6.022x10^23 molecules/mol).
Step 4: Calculate the moles of H2O produced.
From the mole ratio calculated in Step 2, we know that for every mole of C3H8, 4 moles of H2O are produced. Therefore, the moles of H2O produced can be calculated as:
Moles of H2O = (Moles of C3H8) * (4 moles of H2O / 1 mole of C3H8).
Step 5: Convert moles of H2O to grams.
The molar mass of water (H2O) is 18 g/mol. We can use this value to convert the moles of H2O to grams.
Grams of H2O = (Moles of H2O) * (18 g/mol).
By following these steps and plugging in the given values, you can calculate the number of grams of H2O produced from the reaction of 8.5x10^22 molecules of propane gas (C3H8).