one side of a right triangle has 2cm less than the hypothuse, and 7cm more than the third side
what is the lenghnt of each side
The one side = s, other side = s-7, hypotenuse = s+2
Use Pythagorean theorem.
s^2 + (s-7)^2 = (s+2)^2
Solve for s and then the other sides.
I hope this helps.
To find the lengths of the sides of the right triangle, we can use the information given in the problem. Let's call the length of the hypotenuse "c", the shorter side "a", and the longer side "b".
According to the problem, one side of the right triangle has 2cm less than the hypotenuse. So we can say that a = c - 2.
It also states that this side is 7cm more than the third side. Therefore, we can say that a = b + 7.
Now we have two equations:
1. a = c - 2
2. a = b + 7
To solve for the lengths, we can substitute the value of "a" from equation 2 into equation 1:
b + 7 = c - 2
Now we have two equations with two unknowns, "b" and "c".
To further simplify, we can rearrange equation 2 to solve for "b":
b = a - 7
Substituting this into equation 1, we get:
a - 7 + 7 = c - 2
a = c - 2
Since both equations are now equal to "a", we can set them equal to each other:
c - 2 = a
c - 2 = b + 7
Now we have a system of equations:
c - 2 = a
c - 2 = b + 7
We can solve this system using substitution or elimination. Let's use substitution:
From the first equation, we can rewrite it as c = a + 2.
Now we can substitute this value of c in the second equation:
a + 2 - 2 = b + 7
a = b + 7
Since both equations are now equal to "a", we can set them equal to each other:
b + 7 = a
a = b + 7
Now we have a system of equations again:
a = b + 7
b + 7 = a
Substitute the second equation into the first equation:
b + 7 = b + 7 + 7
b + 7 - b = b + 7 + 7 - b
7 = 14
Uh-oh, there seems to be an error in the problem or the calculations made. Please double-check the given information and try again.