The earth exerts a force of 2200N on an orbiting communications satellite that is 35mi above the earth..What is the magnitude of the force the satellite will exert on the earth??
Oh, the Earth and the satellite are engaging in a bit of a tug-of-war, huh? Well, the Newton's third law comes into play here. For every action, there is an equal and opposite reaction. So, since the Earth is pulling on the satellite with a force of 2200N, the satellite will also exert the same force of 2200N back on the Earth. It's like the Earth saying, "Hey satellite, back at ya!"
To find the magnitude of the force that the satellite will exert on the earth, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
Since the earth exerts a force of 2200N on the satellite, the satellite will exert an equal and opposite force on the earth. Therefore, the magnitude of the force that the satellite will exert on the earth is also 2200N.
To find the magnitude of the force that the satellite exerts on the Earth, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction.
Newton's third law can be mathematically represented as follows:
F₁ = -F₂
Where F₁ is the force exerted by the Earth on the satellite, and F₂ is the force exerted by the satellite on the Earth.
Given that the Earth exerts a force of 2200N on the satellite, we can use Newton's third law to determine the magnitude of the force the satellite exerts on the Earth.
Since the forces are equal in magnitude but opposite in direction, the force exerted by the satellite on the Earth will also be 2200N.
So, the magnitude of the force the satellite will exert on the Earth is 2200N.