Find the slope, if it exists.
60x-40y+15=0. I'm stumped on this problem Could someone please help.? Thanks.
My answer was m=2 but it was counted wrong.
To find the slope of the line represented by the equation 60x - 40y + 15 = 0, we need to rearrange the equation into slope-intercept form, which is y = mx + b. The slope (m) will be the coefficient of x.
Let's begin by isolating the term involving y:
60x - 40y + 15 = 0
-40y = -60x - 15
Next, divide the entire equation by -40 to solve for y:
-40y / -40 = (-60x - 15) / -40
y = (60/40)x + (15/40)
Now, simplify the fractions:
y = (3/2)x + (3/8)
Finally, we can see that the coefficient of x is 3/2, which is the slope. Therefore, the slope of the line is 3/2.