how do you figure out electronic configuration of excited state?
ex: identify atom & write ground state conig.
1s2 2s2 2p6 4s1
Isn't there eleven electrons here? Element number 11 is...
1s23s
Chromium
To determine the electronic configuration of an excited state, you need to know the number of electrons and the atom you are studying. In this case, the atom has 11 electrons and based on your hint, we can surmise that it is the element with atomic number 11, which is sodium (Na).
To write the ground state electron configuration of sodium (Na), we start by filling the orbitals in order of increasing energy levels. The order of filling is 1s, 2s, 2p, 3s, and so on. The electronic configuration of the ground state of sodium is:
1s2 2s2 2p6 3s1
This configuration indicates that the first energy level (n=1) contains 2 electrons in the 1s orbital, the second energy level (n=2) contains 2 electrons in the 2s orbital, and 6 electrons in the 2p orbital. Finally, the third energy level (n=3) contains 1 electron in the 3s orbital.
Now, to determine the electron configuration of the excited state, we need to know which electron has been excited. In this case, you mentioned that the configuration given (1s2 2s2 2p6 4s1) seems to have 11 electrons. However, this does not match the electron configuration of sodium in its excited state. It seems to be a different element or an error has occurred.
To correctly determine the excited state configuration, you need to provide more information about the atom and the specific electron(s) that have been excited.