How many grams of iron ion are in 11 grams of K3Fe(C2O4)3?
11 g/molar mass K3Fe(C2O4)3 = moles of that compound.
There is one (1) iron atom in 1 molecule of K3Fe(C2O4)3.
To determine the number of grams of iron ion in 11 grams of K3Fe(C2O4)3, we need to first understand the composition of the compound and then calculate the molar mass.
Step 1: Understand the composition
The compound K3Fe(C2O4)3 consists of potassium ions (K+), iron ions (Fe3+), and oxalate ions (C2O4^2-).
Step 2: Calculate the molar mass
The molar mass is the sum of the atomic masses of all the atoms in the compound. To calculate the molar mass of K3Fe(C2O4)3, we need to know the atomic masses of potassium (K), iron (Fe), carbon (C), and oxygen (O).
- Atomic mass of K: 39.10 g/mol
- Atomic mass of Fe: 55.85 g/mol
- Atomic mass of C: 12.01 g/mol
- Atomic mass of O: 16.00 g/mol
Now, let's calculate the molar mass of K3Fe(C2O4)3:
(3 x atomic mass of K) + atomic mass of Fe + (3 x (atomic mass of C + 2 x atomic mass of O))
(3 x 39.10 g/mol) + 55.85 g/mol + (3 x (12.01 g/mol + 2 x 16.00 g/mol))
117.30 g/mol + 55.85 g/mol + (3 x (12.01 g/mol + 32.00 g/mol))
117.30 g/mol + 55.85 g/mol + (3 x 44.01 g/mol)
117.30 g/mol + 55.85 g/mol + 132.03 g/mol
305.18 g/mol
Step 3: Calculate the amount of iron ions
Now that we know the molar mass of K3Fe(C2O4)3 is 305.18 g/mol, we can calculate the number of moles of K3Fe(C2O4)3 in 11 grams by using the equation:
moles = mass (g) / molar mass (g/mol)
moles = 11 g / 305.18 g/mol
moles ≈ 0.036 moles
Since the ratio between K3Fe(C2O4)3 and Fe ions is 1:1, the amount of iron ions in moles is also 0.036 moles.
Step 4: Convert moles to grams of iron ions
To convert moles of iron ions to grams, we need to use the molar mass of iron (Fe) which is 55.85 g/mol.
grams = moles x molar mass
grams = 0.036 moles x 55.85 g/mol
grams ≈ 2.01 grams
Therefore, there are approximately 2.01 grams of iron ions in 11 grams of K3Fe(C2O4)3.