The difference of two numbers is 9. The sum of 3 times the greater number and 4 more than the lesser number is 51. What are the two numbers?
I do not get this question... I have tried many times, but can not get it.. please help!
thank you.
L-S=9
3L+S+4=51
can you take it from here?
the sum of two numbers is 20. the greater number is 4 more than the lesser. what are the two numbers? write the equation.
Of course, I can help you understand and solve this problem step by step.
Let's assume the greater number is x and the lesser number is y.
From the given information, we can write two equations:
1) The difference of the two numbers is 9:
x - y = 9
2) The sum of 3 times the greater number and 4 more than the lesser number is 51:
3x + (y + 4) = 51
Now, we have a system of two equations with two variables. We can solve this system using substitution or elimination method.
Let's solve it using the substitution method.
From the first equation, we can express x in terms of y:
x = y + 9
Substituting this expression into the second equation, we get:
3(y + 9) + (y + 4) = 51
Now, we can simplify and solve for y:
3y + 27 + y + 4 = 51
4y + 31 = 51
4y = 51 - 31
4y = 20
y = 20/4
y = 5
Now that we have the value of y, we can substitute it back into the first equation to find x:
x - 5 = 9
x = 9 + 5
x = 14
So the two numbers are 14 and 5.
To check our solution, we can substitute these values into the second equation:
3(14) + (5 + 4) = 42 + 9 = 51
Therefore, our solution is correct. The two numbers are 14 and 5.