supoose you want to heat 440g of water by 20 C how many joules of heat are required.
Your school subject is NOT Ashworth.
You named the school subject Ashworth yesterday, also, and Writeacher wrote chemistry. You got an answer that way. You should learn from experience..
q = mass x specific heat x delta T.
To calculate the amount of heat required to heat a substance, you can use the equation:
Q = m * c * ΔT
Where:
- Q represents the amount of heat energy measured in joules (J)
- m represents the mass of the substance in grams (g)
- c represents the specific heat capacity of the substance (water in this case) measured in joules per gram per degree Celsius (J/g°C)
- ΔT represents the change in temperature of the substance in degrees Celsius (°C)
Let's break down the calculation step by step:
Step 1: Determine the mass of water (m)
You already mentioned that the mass of the water is 440g, so we'll use that value.
m = 440g
Step 2: Identify the specific heat capacity of water (c)
The specific heat capacity of water is approximately 4.18 J/g°C. It means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
c = 4.18 J/g°C
Step 3: Calculate the change in temperature (ΔT)
You mentioned that the temperature change is 20°C. Since we're heating the water, the ΔT will be positive.
ΔT = 20°C
Step 4: Plug the values into the equation and calculate Q
Q = m * c * ΔT
= 440g * 4.18 J/g°C * 20°C
Q ≈ 36992 J (joules)
Therefore, approximately 36992 joules of heat are required to heat 440g of water by 20°C.