The instant before a batter hits a .14 KG baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second eat. The bat and ball are in contact for 1.0 x 10 ^-2 second.

How do I determine the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat?

1100

To determine the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat, you can use the following steps:

Step 1: Determine the change in velocity of the baseball.

The change in velocity can be calculated by subtracting the initial velocity from the final velocity. In this case, the initial velocity is 45 m/s west, and the final velocity is 35 m/s east.

Change in velocity = Final velocity - Initial velocity
Change in velocity = 35 m/s east - (-45 m/s west)
Change in velocity = 35 m/s + 45 m/s
Change in velocity = 80 m/s

Step 2: Determine the time taken for the change in velocity.

The given information states that the ball and bat are in contact for 1.0 x 10^-2 seconds.

Time = 1.0 x 10^-2 s

Step 3: Calculate the magnitude of average acceleration.

The magnitude of average acceleration can be calculated using the formula:

Average acceleration = Change in velocity / Time

Average acceleration = 80 m/s / (1.0 x 10^-2 s)
Average acceleration = 80 m/s / 0.01 s
Average acceleration = 8000 m/s^2

Step 4: Determine the direction of average acceleration.

Since the initial velocity is towards the west and the final velocity is towards the east, the average acceleration is in the direction opposite to the initial velocity, i.e., to the east.

Therefore, the magnitude of the average acceleration is 8000 m/s^2, and the direction is east.

To determine the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat, you need to calculate the change in velocity and divide it by the time of contact.

First, calculate the change in velocity by subtracting the initial velocity from the final velocity:
Change in velocity = Final velocity - Initial velocity

Given:
Initial velocity (west) = 45 m/s
Final velocity (east) = -35 m/s (negative because it's in the opposite direction)

Change in velocity = (-35 m/s) - (45 m/s)
= -80 m/s

Next, divide the change in velocity by the time of contact to find the average acceleration:
Average acceleration = Change in velocity / Time of contact

Given:
Time of contact = 1.0 x 10^-2 s

Average acceleration = (-80 m/s) / (1.0 x 10^-2 s)
= -80 m/s / 0.01 s
= -8000 m/s^2

So, the magnitude of the average acceleration is 8000 m/s^2, and the direction is east (since the acceleration is negative, it means it is in the opposite direction of the initial velocity).

the acceleration has to be in the direction it finally goes.

a= changevelociy/time= (-45-35)/.01 m/s where the positive direction is the direction it was thrown.