A solution containing 7.00grm of lead nitrate is combined with a solution containing 7.00g of sodium sulfate.

(a) write a balance equation for the reaction. Pb(no3)2 aq + NaSo4 aq ---> PbSo4 +2 NaNo3. I think that's right.
(b)How many moles of the the product are formed? Is the product PbSo4 , 2NaNo3 or both?
Confused.

Pb(no3)2 aq + NaSo4 aq ---> PbSo4 +2 NaNo3. I think that's right.

except that o is oxygen. n isn't nitrogen. Sodium sulfate is Na2SO4.

1. Convert 7.00 g Pb(NO3)2 to moles. moles = grams/molar mass.
2. Convert 7.00 g Na2SO4 to moles. Same procedure.
3a. Using the coefficients in the balanced equation, convert moles Pb(NO3)2 to moles PbSO4.
3b. Same procedure, convert moles Na2SO4 to moles PbSO4.
3c. Likely, the answers from 3a and 3b will be different which means one of them is wrong. The correct moles PbSO4 formed is ALWAYS the smaller value.

4. The question doesn't ask for grams PbSO4, but you can convert the smaller value in 3c to grams. g = moles x molar mass.

The ppt is PbSO4 because it is insoluble. NaNO3 is soluble and if filtered can be separated from the solid PbSO4.

Thank you so much you genius!!!!

Sorry, Maybe this is so simple its confusing me. Converting Pb(No3)2 to PbSo4 and Na2So4 to Pbso4 using the coefficients. Would it be 1 to 1?

(a) The balanced equation for the reaction between lead nitrate (Pb(NO3)2) and sodium sulfate (Na2SO4) is:

Pb(NO3)2 (aq) + Na2SO4 (aq) → PbSO4 (s) + 2NaNO3 (aq)

In this equation, the lead nitrate and sodium sulfate react to form lead(II) sulfate (PbSO4) as a solid product and sodium nitrate (NaNO3) as a soluble product.

(b) To determine the number of moles of the product formed, we need to consider the stoichiometry of the balanced equation. From the balanced equation, we can see that 1 mole of Pb(NO3)2 reacts with 1 mole of Na2SO4 to produce 1 mole of PbSO4 and 2 moles of NaNO3.

Since the molar mass of PbSO4 is 303.26 g/mol, we can calculate the number of moles using the formula:

Moles = Mass / Molar mass

To calculate the moles of PbSO4 formed, divide the mass of the PbSO4 (which is equal to the total mass of the products since only one product is solid) by its molar mass:

Moles of PbSO4 = 7.00 g / 303.26 g/mol

To calculate the moles of NaNO3 formed, we consider that for every mole of PbSO4 formed, 2 moles of NaNO3 are also produced:

Moles of NaNO3 = 2 × Moles of PbSO4

So, to determine both the moles of PbSO4 and NaNO3, we need to calculate the moles of PbSO4 first using the given mass and molar mass, and then multiply that by 2 to find the moles of NaNO3.