How much heat (in Joules) is gained by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 15C?
heat=masswater*specificheatwater*15
I assume you know the density of water.
Well, that depends on how funny you find chemistry jokes! Ready for one?
Why was the math book sad after the chemistry book broke up with it?
Because it lost all of its significant figures!
Alright, alright, let's get back to the question. To calculate the heat gained by the water, we can use the equation:
Q = m * c * ΔT
Where:
Q = heat gained by the water (in Joules)
m = mass of water (in grams)
c = specific heat capacity of water (in J/g°C)
ΔT = temperature change (in °C)
Given that the solution is 100 mL, we need to convert it to grams. Assuming the density of water is 1 g/mL, we have:
m = 100 mL * 1 g/mL = 100 grams
The specific heat capacity of water is approximately 4.18 J/g°C, so:
Q = 100 g * 4.18 J/g°C * 15°C
Q = 6270 J
So, approximately 6270 Joules of heat would be gained by the water in this chemical reaction.
To calculate the heat gained by the water, we can use the formula:
Q = mcΔT
Where:
Q is the heat gained (in Joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (4.18 J/g·°C)
ΔT is the change in temperature (in °C)
First, let's find the mass of the water in the solution. The density of water is approximately 1 g/mL.
Mass of water = volume of water × density
= 100 mL × 1 g/mL
= 100 g
Now we can substitute the values into the formula:
Q = mcΔT
= (100 g) × (4.18 J/g·°C) × (15°C)
≈ 6270 J
Therefore, the water gains approximately 6270 Joules of heat.
To calculate the heat gained by the water, we can use the equation:
Q = mcΔT
Where:
Q is the heat gained or lost by the water (in Joules),
m is the mass of the water (in grams),
c is the specific heat capacity of water (4.184 J/g°C), and
ΔT is the change in temperature (in °C).
In this case, we need to convert the volume of water (100 mL) into mass (grams) before we can proceed. To do that, we'll need to know the density of water:
Density of water = 1 g/mL
So, the mass of the water can be calculated as follows:
mass = volume × density
mass = 100 mL × 1 g/mL
mass = 100 g
Now that we have the mass of the water, we can calculate the heat gained using the equation mentioned earlier:
Q = mcΔT
Q = 100 g × 4.184 J/g°C × 15°C
Q ≈ 62,760 J
Therefore, the water gains approximately 62,760 Joules of heat in this chemical reaction.