How much heat (in Joules) is gained by the water where a chemical reaction takes place in 100 mL aqueous solution and has a temperature increase of 15C?
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To find the heat gained by the water in this chemical reaction, you need to use the equation Q = m × c × ΔT, where Q represents the heat gained or lost, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
Step 1: Determine the mass of water.
You are given that the reaction takes place in a 100 mL aqueous solution. To find the mass, you need to convert mL to grams. The density of water is about 1 g/mL, so the mass of water can be calculated as 100 grams.
Step 2: Find the specific heat capacity of water.
The specific heat capacity of water is approximately 4.184 J/g°C. This value represents the amount of heat energy required to raise the temperature of 1 gram of water by 1 degree Celsius.
Step 3: Calculate the heat gained.
Now, plug in the values into the formula Q = m × c × ΔT:
Q = (100 g) × (4.184 J/g°C) × (15°C)
Q = 6276 J
Therefore, the water gains approximately 6276 Joules (J) of heat during the chemical reaction.