How many grams of NaN3 are required to produce 17.4 ft3 of nitrogen gas?
1. Write the balanced chemical equation.
2. Convert 17.4 cubic feet N2 to liters. Then convert liters to moles. I assume this is at STP.
3. Using the coefficients in the balanced equation, convert moles N2 to moles NaN3.
4. Convert moles NaN3 to grams. g = moles x molar mass.
Post your work if you get stuck.
2.01
To determine how many grams of NaN3 are required to produce 17.4 ft3 of nitrogen gas, we need to follow several steps.
Step 1: Write and balance the chemical equation:
2 NaN3 → 2 Na + 3 N2
Step 2: Calculate the molar ratio:
From the balanced equation, we can see that 2 moles of NaN3 react to produce 3 moles of nitrogen gas.
Step 3: Convert ft3 to liters:
To make the units consistent, we need to convert the volume from ft3 to liters.
1 ft3 is approximately equal to 28.3168 liters. Thus, 17.4 ft3 is equal to 491.24632 liters.
Step 4: Convert liters to moles:
Using the ideal gas law with standard temperature and pressure (STP), one mole of any gas occupies 22.414 liters at 0 degrees Celsius and 1 atmosphere of pressure. Therefore, we need to calculate the number of moles of nitrogen gas in 491.24632 liters.
Moles of nitrogen gas = Volume in liters / 22.414
Step 5: Calculate moles of NaN3:
Since the molar ratio of NaN3 to nitrogen gas is 2:3, we can calculate the moles of NaN3 required.
Moles of NaN3 = Moles of nitrogen gas × (2 moles of NaN3 / 3 moles of N2)
Step 6: Calculate grams of NaN3:
Once we have the moles of NaN3, we can calculate the grams using the molar mass of NaN3, which is approximately 65 grams/mol.
Grams of NaN3 = Moles of NaN3 × Molar mass of NaN3
By following these steps, you can calculate the grams of NaN3 required to produce 17.4 ft3 of nitrogen gas.