What is the volume of 0.25M PMSF & volume of 14.3M 2-mercaptoethanol needed in 25 mL of 20 mM sodium phosphate?
MW of sodium sulfate = 137.99
What, pray tell, is PMSF. And what is the question?
it's just a solution.
I'm not sure how to find the volume dilution... this is a dilution problem.
To determine the volume of 0.25M PMSF and 14.3M 2-mercaptoethanol needed in 25 mL of 20 mM sodium phosphate, we can follow these steps:
1. Calculate the moles of sodium phosphate:
To do this, we need to multiply the concentration (20 mM) by the volume (25 mL) and convert it to moles. Remember, 1 mM = 1 mmol/L.
Moles of sodium phosphate = concentration (M) x volume (L)
Moles of sodium phosphate = 20 mM x 25 mL / 1000 mL/L
Moles of sodium phosphate = 0.5 mmol
2. Calculate the volume of 0.25M PMSF:
We need to have a 0.5 mmol of sodium phosphate in the final solution. Since the concentration of PMSF is given as 0.25M, we can use the following formula to calculate the volume of PMSF:
Volume of PMSF (L) = Moles of PMSF / Concentration of PMSF (M)
Volume of PMSF (L) = 0.5 mmol / 0.25 M
Volume of PMSF (L) = 2 mL
3. Calculate the volume of 14.3M 2-mercaptoethanol:
Similar to the above step, we can use the same formula to calculate the volume of 2-mercaptoethanol:
Volume of 2-mercaptoethanol (L) = Moles of 2-mercaptoethanol / Concentration of 2-mercaptoethanol (M)
Volume of 2-mercaptoethanol (L) = 0.5 mmol / 14.3 M
Volume of 2-mercaptoethanol (L) = 0.035 L or 35 mL
So, the volume of 0.25M PMSF needed is 2 mL, and the volume of 14.3M 2-mercaptoethanol needed is 35 mL.