Determine the boiling point elevation of H2O in the following solution
a 2.5 m solution of C6H12O6 in H2O
All i need is the formulas because i don't know how to solve it
Thank you
:l
moles = grams/molar mass.
Calculate moles C6H12O6.
m = moles/kg solvent.
Calculate m of the solution.
Delta T = kb*m
Calculate delta T.
O.o where do i get the grams from m=grams/molar mass?
You don't and you don't need that step or the next one. I just included them because most problems require the three steps. In this case, you already have molality given so you already have the first two. Just substitute into the third step, delta T = Kb*m.
:D
thank you
To determine the boiling point elevation of a solution, you need to use the formula:
∆Tb = Kb * m
Where:
∆Tb is the boiling point elevation,
Kb is the molal boiling point elevation constant (specific for the solvent),
m is the molality of the solute.
For water (H2O), the molal boiling point elevation constant (Kb) is approximately 0.512 °C/m.
To solve for ∆Tb, you need to calculate the molality (m) of the solute (C6H12O6). The molality is defined as:
molality (m) = moles of solute (C6H12O6) / mass of the solvent (H2O in kg)
First, you need to determine the moles of solute. To do this, divide the mass of the solute (C6H12O6) by its molar mass.
Next, determine the mass of the solvent (H2O) by multiplying the volume of the solution by the density of water.
Finally, convert the mass of the solvent to kilograms by dividing by 1000.
Now you can calculate the molality (m) using the formula provided above.
Substitute the molal boiling point elevation constant (Kb) and the molality (m) value into the ∆Tb formula, and you will find the boiling point elevation of the solution.
Keep in mind that the boiling point elevation is the difference between the boiling point of the solution and the boiling point of the pure solvent. So, to find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water, which is 100 °C.