What is the balaced net ionic for this equation:
PbNO3+CuSO4-->PbSO4+CuNO3
To determine the balanced net ionic equation for the given chemical reaction:
Step 1: Write the balanced molecular equation:
Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2
Step 2: Write the complete ionic equation by separating the soluble ionic compounds into their respective ions:
Pb2+(aq) + 2NO3-(aq) + Cu2+(aq) + SO42-(aq) → PbSO4(s) + Cu2+(aq) + 2NO3-(aq)
Step 3: Identify the spectator ions (ions that appear on both sides of the arrow and do not undergo a chemical change) and remove them from the equation:
Pb2+(aq) + SO42-(aq) → PbSO4(s)
Step 4: Write the balanced net ionic equation using only the species that actively participate in the reaction:
Pb2+(aq) + SO42-(aq) → PbSO4(s)
Thus, the balanced net ionic equation for the given reaction is: Pb2+(aq) + SO42-(aq) → PbSO4(s)
To determine the balanced net ionic equation for the given equation:
1. Start by writing the complete balanced equation, including the complete ionic equation and spectator ions:
Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2
This equation represents the reactants and products in their complete ionic forms, with all of their respective ions written out explicitly.
2. Next, identify the ions that remain unchanged in the reaction and are present on both sides of the equation. These ions are known as spectator ions and are not directly involved in the chemical reaction. In this case, the spectator ions are nitrate ions (NO3-) and sulfate ions (SO42-).
3. Remove the spectator ions from the equation to obtain the net ionic equation. The remaining ions are the ones directly involved in the reaction.
The net ionic equation for the reaction P
Pb^+2 + SO4^-2 ==> PbSO4(s)
You made two errors in your post. The last material should be Cu(NO3)2 and the first material should be Pb(NO3)2