NEED HELP ASAP PLEASE!!
A high sound level of 120 dB is regarded as the threshold of pain for the average listener. If the threshold of hearing is 10^−12 watts/m^2, then the intensity of the sound corresponding to 120 dB is
____________ watts/m^2.
chicken
This is a standard formula.
intensity=10log(power/thresholdhearing)
So
I get......
10log(120/10^-12) = 140.7918125
But its incorrect :(
what am I doing wrong ?
To find the intensity of the sound corresponding to 120 dB, we can use the equation:
Intensity (in watts/m^2) = Threshold of hearing (in watts/m^2) * 10^(sound level in dB/10)
First, let's convert the given sound level of 120 dB to intensity using the equation.
Intensity = 10^(-12 watts/m^2) * 10^(120 dB/10)
Now, let's solve this equation step by step.
First, let's calculate 120 dB divided by 10:
120 dB/10 = 12 dB
Next, let's calculate 10^(12 dB):
10^(12 dB) = 10^12
Finally, let's multiply the threshold of hearing (10^(-12 watts/m^2)) by 10^12 to find the intensity:
Intensity = 10^(-12 watts/m^2) * 10^12
Now, let's simplify this equation:
Intensity = 1 watt/m^2
Therefore, the intensity of the sound corresponding to 120 dB is 1 watt/m^2.