What is the acceleration of the system if both blocks have a mass of 5.0 kg, and the coefficient of kinetic friction is 0.11?
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(b) Determine the tension in the rope.
Acceleration is
Delta V, over Delta T which equals
V2-V1, over Delta T
Delta referring to the change in velocity and change in time
To determine the acceleration of the system with blocks of mass 5.0 kg and a coefficient of kinetic friction of 0.11, we can use Newton's second law of motion. This law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the net force acting on the system is given by the tension in the rope minus the force of friction. The force of friction can be calculated using the formula:
Force of friction = coefficient of kinetic friction * normal force.
The normal force is the force exerted by a surface perpendicular to the contact surface. Here, it is equal to the weight of the block, which is given by the formula:
Weight = mass * acceleration due to gravity.
The acceleration due to gravity is approximately 9.8 m/s^2.
Once we have the force of friction, we can use it to derive the net force acting on the system. Then, we can divide this net force by the total mass of the two blocks to calculate acceleration.
Next, to determine the tension in the rope, we need to consider the forces acting on the individual blocks. The tension in the rope is the same for both blocks, and it acts in the direction of motion. The tension force can be found using the formula:
Tension = mass * acceleration + force of friction.
By substituting the known values into the formulas, we can calculate the desired values.
We have no idea what "the system" is.
In physics, a descriptive labeled figure is often an important part of the problem. It isn't just answering word problems or plugging numbers into equations in a book.