In rhombus PQSR, PQ=y+8 and QS = 4y-7. Find PQ.
Also...
In rectangle ABCD,AB=x+15, BC=x-8, and CD=2x+3.
Find: 1)x. 2)AB 3)BC
Thanks!
To find the length of a line segment in a shape, we need to know the lengths of the other sides or have additional information. Let's consider each question one by one.
1) In rhombus PQSR, we are given the lengths of two sides: PQ = y+8 and QS = 4y-7. However, we don't have enough information to find the exact length of PQ since we don't know the value of y or any other side lengths.
If you have more information about the rhombus, such as an additional side length or an angle measure, please provide it so I can help you further.
Now, let's move on to the next question:
2) In rectangle ABCD, we are given the lengths of three sides: AB = x+15, BC = x-8, and CD = 2x+3. We can use this information to find the value of x and then use it to calculate the lengths of AB and BC.
Since ABCD is a rectangle, opposite sides are equal in length. Therefore, AB = CD and BC = AD.
Setting AB equal to CD, we have:
x + 15 = 2x + 3
Simplifying the equation, we get:
15 = x + 3
Subtracting 3 from both sides:
12 = x
So x = 12.
Now we can substitute x=12 into the expressions for AB and BC:
AB = 12 + 15 = 27
BC = 12 - 8 = 4
Therefore, the answers are:
1) x = 12
2) AB = 27
3) BC = 4
If you have any further questions or need additional assistance, feel free to ask.