there is a triangle with a base of 2.4 m and both sides are 1.7 m. it is a right triangle. what the heck is the answer? i have an answer sheet and i know the answer is 41 but how do you get that answer?
well what the heck is the question!?
i need to find the area
A = B*H/2-what's the height?
It is "almost" a right - angled triangle.
1.7^2 + 1.7^2 = 5.78
2.4^2 = 5.76 , close but not right-angled
anyway, ...
Area is(almost) = (1/2)base(height)
= (1/2)1.7(1.7) = 1.4
which is not what you gave.
FOUND IT
To find the answer, you can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the base of the triangle is 2.4 m, and both sides (legs) are 1.7 m. Let's assume the base is the side adjacent to the right angle, and the 1.7 m sides are the other two sides.
So, let's denote the base as side A (2.4 m), and the two other sides as B and C (both 1.7 m).
According to the Pythagorean theorem: A^2 = B^2 + C^2
Substituting the values we have: (2.4)^2 = (1.7)^2 + (1.7)^2
Simplifying: 5.76 = 2.89 + 2.89
Adding: 5.76 = 5.78
This means that there seems to be an error in the answer sheet you mentioned. The correct solution should be 5.76, not 41.