Balance the following equation:

C6H5COOH + O2 ==> H2O + CO2

2C6H5COOH +15 O2 ==> 6H2O + 14CO2

Check this to see if it is correct

To balance the equation: C6H5COOH + O2 ==> H2O + CO2, we need to make sure that there are an equal number of each type of atom on both sides of the arrow.

Let's start by counting the atoms on each side of the equation:
On the left-hand side, we have: 1 carbon (C), 8 hydrogen (H), 2 oxygen (O).
On the right-hand side, we have: 2 hydrogen (H), 3 oxygen (O), and 1 carbon (C).

To balance the carbons, we can place a coefficient of 1 in front of CO2 on the right-hand side:
C6H5COOH + O2 ==> H2O + 2CO2

Next, we balance the hydrogens. We currently have 5 hydrogens on the left and 2 hydrogens on the right. To equalize them, we can place a coefficient of 4 in front of H2O on the right-hand side:
C6H5COOH + O2 ==> 4H2O + 2CO2

Finally, we balance the oxygens. On the left-hand side, we have 2 oxygen atoms from O2, while on the right-hand side, we have 12 oxygen atoms from 4H2O and 2CO2 combined. To balance the oxygens, we can place a coefficient of 6 in front of O2 on the left-hand side:
C6H5COOH + 6O2 ==> 4H2O + 2CO2

The final balanced equation is:
C6H5COOH + 6O2 ==> 4H2O + 2CO2