Part A) A 2.2 kg rock is released from rest at the surface of a pond 1.8 m deep. As the rock falls, a constant upward force of 5.0 N is exerted on it by water resistance. Let y=0 be at the bottom of the pond. Calculate the nonconservative work, Wnc , done by water resistance on the rock, the gravitational potential energy of the system, U , the kinetic energy of the rock, K , and the total mechanical energy of the system, E , when the depth of the rock below the water's surface is 0 m.

Part B) What is the Wnc of the water resistance on the rock, U, K, and E when the rock is 0.50 m below the surface?
Part C) What is the Wnc of the water resistance on the rock, U, K, and E when the rock is 1.0 m below the surface?

To solve this problem, we need to use the principles of work, potential energy, and kinetic energy.

Part A:
1. First, let's calculate the nonconservative work done by water resistance on the rock. The nonconservative work, Wnc, is given by the equation Wnc = F * d, where F is the force applied and d is the displacement. In this case, the force exerted by water resistance is 5.0 N, and the displacement is 1.8 m (the depth of the pond). Therefore, Wnc = 5.0 N * 1.8 m = 9.0 J.

2. Next, let's calculate the gravitational potential energy of the system. The formula for gravitational potential energy, U, is given by U = m * g * h, where m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and h is the height or depth. In this case, m = 2.2 kg and h = 1.8 m. Therefore, U = 2.2 kg * 9.8 m/s^2 * 1.8 m = 38.808 J (rounded to three decimal places).

3. Now, let's calculate the kinetic energy of the rock. The formula for kinetic energy, K, is given by K = 0.5 * m * v^2, where m is the mass and v is the velocity. Since the rock is released from rest, its initial velocity is 0 m/s. Therefore, K = 0.5 * 2.2 kg * (0 m/s)^2 = 0 J.

4. Finally, let's calculate the total mechanical energy of the system, E. The total mechanical energy is the sum of potential energy and kinetic energy, so E = U + K = 38.808 J + 0 J = 38.808 J.

Part B:
1. Similarly, when the rock is 0.50 m below the surface, the nonconservative work, Wnc, is still 9.0 J since the force and displacement remain the same.

2. The gravitational potential energy, U, is given by U = m * g * h, where m = 2.2 kg and h = 0.50 m. Therefore, U = 2.2 kg * 9.8 m/s^2 * 0.50 m = 10.780 J (rounded to three decimal places).

3. The kinetic energy, K, is still 0 J because the rock is not moving.

4. The total mechanical energy, E, is E = U + K = 10.780 J + 0 J = 10.780 J.

Part C:
1. When the rock is 1.0 m below the surface, the nonconservative work, Wnc, remains 9.0 J.

2. The gravitational potential energy, U, is given by U = m * g * h, where m = 2.2 kg and h = 1.0 m. Therefore, U = 2.2 kg * 9.8 m/s^2 * 1.0 m = 21.560 J (rounded to three decimal places).

3. The kinetic energy, K, is still 0 J as the rock is not moving.

4. The total mechanical energy, E, is E = U + K = 21.560 J + 0 J = 21.560 J.

That's how you calculate the nonconservative work, gravitational potential energy, kinetic energy, and total mechanical energy at different depths below the water's surface.

Someone will gladly critique your work.

Nonconservative work done is the product of the water resistance force and the distance it has fallen.

They have not mentioned the density of the rock. There will be a buoyancy force on the rock that should be considered, so some of the answers they want may not be the correct ones