Chem = )

Write the complete ionic equation for

BaCl2 + NaOH ---->

Al2(SO4)3 + BaCl2 --->

Al2(SO4)3 + NaOH --->

NaOH + Zn(No3)2 --->

BaCl2 + NaI --->

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  1. I will do one. First one products would be Ba(OH2), but that is insoluble, a reaction occurs. NaCL...that is soluble, no reaction
    Net Ionic:
    Ba++ + 2OH->> Ba(OH)2 (s)
    Complete Ionic:
    Ba2+ + 2Cl- + 2Na+ + 2OH- >> Ba(OH)2 (s) + 2Na+ + 2Cl-

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