Write the complete ionic equation for
BaCl2 + NaOH ---->
Al2(SO4)3 + BaCl2 --->
Al2(SO4)3 + NaOH --->
NaOH + Zn(No3)2 --->
BaCl2 + NaI --->
I will do one. First one products would be Ba(OH2), but that is insoluble, a reaction occurs. NaCL...that is soluble, no reaction
Net Ionic:
Ba++ + 2OH->> Ba(OH)2 (s)
Complete Ionic:
Ba2+ + 2Cl- + 2Na+ + 2OH- >> Ba(OH)2 (s) + 2Na+ + 2Cl-
To write the complete ionic equations for the given chemical reactions, we need to break down the reactants and products into their individual ions. The ions that stay as ions (known as spectator ions) will not participate in the reaction and can be omitted from the equation. Here are the complete ionic equations for each reaction:
1) BaCl2 + NaOH -> Ba(OH)2 + NaCl
Breaking down the compounds into ions:
BaCl2 (aq) + 2NaOH (aq) -> Ba(OH)2 (aq) + 2NaCl (aq)
Complete ionic equation:
Ba^2+ (aq) + 2Cl^- (aq) + 2Na^+ (aq) + 2OH^- (aq) -> Ba(OH)2 (aq) + 2Na^+ (aq) + 2Cl^- (aq)
Simplified ionic equation:
Ba^2+ (aq) + 2OH^- (aq) -> Ba(OH)2 (aq)
2) Al2(SO4)3 + BaCl2 -> BaSO4 + 2AlCl3
Breaking down the compounds into ions:
Al2(SO4)3 (aq) + 3BaCl2 (aq) -> BaSO4 (s) + 2AlCl3 (aq)
Complete ionic equation:
2Al^3+ (aq) + 3SO4^2- (aq) + 6Ba^2+ (aq) + 6Cl^- (aq) -> BaSO4 (s) + 2Al^3+ (aq) + 6Cl^- (aq)
Simplified ionic equation:
3Ba^2+ (aq) + 3SO4^2- (aq) -> BaSO4 (s)
3) Al2(SO4)3 + NaOH -> Al(OH)3 + Na2SO4
Breaking down the compounds into ions:
Al2(SO4)3 (aq) + 6NaOH (aq) -> 2Al(OH)3 (s) + 3Na2SO4 (aq)
Complete ionic equation:
2Al^3+ (aq) + 3SO4^2- (aq) + 6Na^+ (aq) + 6OH^- (aq) -> 2Al(OH)3 (s) + 6Na^+ (aq) + 3SO4^2- (aq)
Simplified ionic equation:
2Al^3+ (aq) + 6OH^- (aq) -> 2Al(OH)3 (s)
4) NaOH + Zn(NO3)2 -> NaNO3 + Zn(OH)2
Breaking down the compounds into ions:
NaOH (aq) + Zn(NO3)2 (aq) -> NaNO3 (aq) + Zn(OH)2 (s)
Complete ionic equation:
Na^+ (aq) + OH^- (aq) + Zn^2+ (aq) + 2NO3^- (aq) -> Na^+ (aq) + NO3^- (aq) + Zn(OH)2 (s)
Simplified ionic equation:
OH^- (aq) + Zn^2+ (aq) -> Zn(OH)2 (s)
5) BaCl2 + NaI -> BaI2 + 2NaCl
Breaking down the compounds into ions:
BaCl2 (aq) + 2NaI (aq) -> BaI2 (s) + 2NaCl (aq)
Complete ionic equation:
Ba^2+ (aq) + 2Cl^- (aq) + 2Na^+ (aq) + 2I^- (aq) -> BaI2 (s) + 2Na^+ (aq) + 2Cl^- (aq)
Simplified ionic equation:
Ba^2+ (aq) + 2I^- (aq) -> BaI2 (s)
The complete ionic equations for the given reactions are as follows:
1. BaCl2 + 2NaOH ---> Ba(OH)2 + 2NaCl
2. Al2(SO4)3 + 3BaCl2 ---> 2AlCl3 + 3BaSO4
3. Al2(SO4)3 + 6NaOH ---> 2Al(OH)3 + 3Na2SO4
4. 2NaOH + Zn(NO3)2 ---> 2NaNO3 + Zn(OH)2
5. BaCl2 + 2NaI ---> BaI2 + 2NaCl