what is the water vapor pressure of water at 29 degrees celsius? i can't find the information anywhere.
A table for you. One estimate you can always make---the vapor pressure water near room temperature is approximately equal in number to the temperature. That is 20 degrees vp about 20 mm Hg, 25 C vp about 25 mm Hg, etc.
http://www.vaxasoftware.com/doc_eduen/qui/pvh2o.pdf
thank you so much for the table!
To find the water vapor pressure of water at 29 degrees Celsius, you can use the Antoine equation. The Antoine equation relates the vapor pressure of a substance to its temperature.
The equation for water is: log10(p) = A - (B / (T + C))
Where p is the vapor pressure in mmHg, T is the temperature in degrees Celsius, and A, B, and C are constants specific to water.
For water, the values of A, B, and C are as follows:
A = 8.07131
B = 1730.63
C = 233.426
Now, substituting the given temperature of 29 degrees Celsius into the equation:
log10(p) = 8.07131 - (1730.63 / (29 + 233.426))
Simplifying the equation gives:
log10(p) = 7.958
Next, we need to solve for p. By converting the equation to exponential form, we get:
p = 10^(7.958)
Calculating this value gives us:
p ≈ 779 mmHg
Therefore, the water vapor pressure at 29 degrees Celsius is approximately 779 mmHg.