need help with doing this combining vector question

A jogger runs with a velocity of 6km/h 25 degrees north west for 35 minutes and then changes direction , jogging for 20 minutes at 4.5km/h 65 degrees east of north. using a vector diagram determine the joggers total displacement and his average velocity for the workout.

I cant help with a vector diagram. What is your question?

i need to determien the displa

To solve this problem, we need to break down the jogger's motion into two separate components: the first component from the initial direction and velocity, and the second component from the changed direction and velocity.

1. Velocity vector for the first component:
The jogger runs with a velocity of 6 km/h at a direction of 25 degrees northwest. To find the vector components, we need to split the velocity into its horizontal and vertical components.

Horizontal component:
cos(25) * 6 km/h = 5.40 km/h

Vertical component:
sin(25) * 6 km/h = 2.54 km/h

Therefore, the velocity vector for the first component is 5.40 km/h horizontally (west) and 2.54 km/h vertically (north).

2. Displacement vector for the first component:
The jogger runs for 35 minutes with the given velocity. Displacement is the change in position. To find the displacement, we need to multiply the velocity vector by the time:

Displacement = Velocity * Time

Horizontal displacement:
5.40 km/h * (35 min / 60 min/h) = 3.15 km

Vertical displacement:
2.54 km/h * (35 min / 60 min/h) = 1.49 km

Therefore, the displacement vector for the first component is 3.15 km horizontally (west) and 1.49 km vertically (north).

3. Velocity vector for the second component:
The jogger runs with a velocity of 4.5 km/h at a direction 65 degrees east of north. Again, we need to find the vector components:

Horizontal component:
cos(65) * 4.5 km/h = 2.15 km/h

Vertical component:
sin(65) * 4.5 km/h = 3.94 km/h

Therefore, the velocity vector for the second component is 2.15 km/h horizontally (east) and 3.94 km/h vertically (north).

4. Displacement vector for the second component:
The jogger runs for 20 minutes at this velocity. We can calculate the displacement using the same formula as before:

Horizontal displacement:
2.15 km/h * (20 min / 60 min/h) = 0.72 km

Vertical displacement:
3.94 km/h * (20 min / 60 min/h) = 1.31 km

Therefore, the displacement vector for the second component is 0.72 km horizontally (east) and 1.31 km vertically (north).

5. To find the total displacement, we add up the respective horizontal and vertical displacements from both components:

Total horizontal displacement: 3.15 km - 0.72 km = 2.43 km (west)

Total vertical displacement: 1.49 km + 1.31 km = 2.80 km (north)

Therefore, the total displacement vector is 2.43 km west and 2.80 km north.

6. To find the average velocity, we divide the total displacement by the total time taken:

Total distance:
(35 min / 60 min/h) + (20 min / 60 min/h) = 0.92 hours

Average horizontal velocity:
2.43 km / 0.92 h = 2.64 km/h (west)

Average vertical velocity:
2.80 km / 0.92 h = 3.04 km/h (north)

Therefore, the average velocity for the workout is 2.64 km/h west and 3.04 km/h north.