If a metal stays solid at Farenheit temperature below 1801.5 degrees. Determine ( in terms of an inequality) those Celsius temperatures for which the metal stays solid. Use the formula F= 9/5C+32.
1801.5=9/5C+32.
Now I'm not sure what to do from here?
Thanks.
solve for C. subtract 32 from both sides and then multiply both sides by 5/9 and you should get C. then the inequality is any temp less than C (<C) keeps the metal solid.
im not 100% sure on the inequality part but i hope this helps...
So would the answer be: 1769.5=9/5C. Then take 5/9 * 1769.5=9/5C*5/9. C= 983.05555. Round to the nearest tenth. C<983.10 degrees. Is this right?
put this in the google search window:
1801.5 degrees F in degrees C
To determine the Celsius temperatures for which the metal stays solid, we can start by rearranging the formula F=9/5C+32 to solve for Celsius temperature (C).
1801.5 = 9/5C + 32
First, we can subtract 32 from both sides of the equation to isolate the term with C:
1769.5 = 9/5C
Next, we can multiply both sides of the equation by 5/9 to solve for C:
C = (1769.5)(5/9)
Simplifying further, we have:
C = 983.0556
Therefore, the metal stays solid at Celsius temperatures below 983.0556. In terms of an inequality, it can be written as:
C < 983.0556