I need to write the net inonic equation for (NH4)2SO4(aq) and KNO2(aq). I need to know the reactants and the product.

I worked it out and got:
2K+(aq) + SO4-(aq) ----> K(SO4)2(s)

I don't know if you made a typo or not but the two materials you have for reactants will not react to produce anything. You could show the (NH4)2SO4 as ions and the KNO2 as ions in the solution as a net ionic equation but there is no reaction as such. Review reasons why a reaction will occur. They are

a. an insoluble material (a ppt) is formed.
b. a gas is formed.
c. a weak electrolyte is formed.
d. a redox reaction.

If ammonia reacts according to the following equation how many kilograms of NO could be produced from 10 kg of NH3 if the percent yield of NO is 80%? 4NH3+ 5O2 yields 4NO+ 6H2O

To write the net ionic equation for the reaction between (NH4)2SO4(aq) and KNO2(aq), we first need to determine the reactants and products of the chemical reaction.

The reactants are (NH4)2SO4(aq) and KNO2(aq). The compound (NH4)2SO4 dissociates into its ions in water:
(NH4)2SO4(aq) → 2NH4+(aq) + SO4-(aq)

Similarly, KNO2 dissociates into its ions:
KNO2(aq) → K+(aq) + NO2-(aq)

Now, we can write the complete ionic equation by combining the dissociated ions from both reactants:
2NH4+(aq) + SO4-(aq) + K+(aq) + NO2-(aq)

Next, we need to identify the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are NH4+ and SO4-.

Finally, we can write the net ionic equation by removing the spectator ions from the complete ionic equation:
2K+(aq) + NO2-(aq)

Therefore, the net ionic equation for the reaction between (NH4)2SO4(aq) and KNO2(aq) is:
2K+(aq) + NO2-(aq)