Write the equation
an absolute value function is shifted up 2 units shifted right 3 units and horizontally stretched by 5
y= abs[5(x-3)] +2 try that
5 was circled and it said it was wrong i am confused thanks anyway
which equation is an absolute value graph shifted right 5
The equation of an absolute value function can be written as:
f(x) = a |x - h| + k
In this case, the function is shifted up 2 units, shifted right 3 units, and horizontally stretched by 5.
To incorporate the vertical shift, we set k = 2.
To incorporate the horizontal shift, we set h = -3.
The equation now becomes:
f(x) = a |x - (-3)| + 2
To incorporate the horizontal stretch by a factor of 5, we divide the absolute value expression by 5.
The equation is now:
f(x) = a |(x - (-3))/5| + 2
Therefore, the equation of the absolute value function that is shifted up 2 units, shifted right 3 units, and horizontally stretched by 5 is:
f(x) = a |(x + 3)/5| + 2