What is the balanced ionic equation between bromine and sodium bisulfite??? thanks
Not including the sodium ion Na+, as it is a spectator ion:
Br2 + HSO3(-) + H2O --> 2Br(-) + SO4(2-) + 3H(+)
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
NaHSO3 + Br2 + H2O --> NaHSO4 + 2HBr
Why did the bromine and sodium bisulfite go on a blind date?
Because they heard they had great chemistry!
Now, let's get down to business. The balanced ionic equation between bromine (Br2) and sodium bisulfite (NaHSO3) can be represented as follows:
3 Br2 + 6 NaHSO3 → 6 NaBr + 3 H2SO4 + S
So, bromine and sodium bisulfite are going to have a chemical reaction party, and the products are sodium bromide (NaBr), sulfuric acid (H2SO4), and a little element of surprise - sulfur (S). Enjoy the show!
To determine the balanced ionic equation between bromine (Br2) and sodium bisulfite (NaHSO3), we first need to understand the chemical formulas of these compounds and their ionization.
Bromine is a diatomic molecule composed of two bromine atoms bonded together (Br2). Sodium bisulfite is an ionic compound consisting of sodium ions (Na+) and bisulfite ions (HSO3-).
The reaction between bromine and sodium bisulfite can be represented by the following chemical equation:
Br2 + NaHSO3 → NaBr + H2SO4
To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Here's how you can balance the equation:
1. Start by balancing the atoms of the most complex molecule or polyatomic ion. In this case, it's the bisulfite ion (HSO3-).
HSO3- + Br2 → NaBr + H2SO4
2. Balance the bromine atoms by placing a coefficient of 2 in front of the bromine molecule (Br2).
HSO3- + 2Br2 → NaBr + H2SO4
3. Balance the sulfur atoms by placing a coefficient of 1 in front of sulfuric acid (H2SO4).
HSO3- + 2Br2 → NaBr + H2SO4
4. Finally, balance the sodium and hydrogen atoms by placing a coefficient of 2 in front of sodium bisulfite (NaHSO3).
2NaHSO3 + 2Br2 → 2NaBr + H2SO4
Thus, the balanced ionic equation between bromine and sodium bisulfite is:
2NaHSO3 + 2Br2 → 2NaBr + H2SO4