What mass in g of NaCl is formed from the reaction of 54.0 mL of a 0.078 M AgC2H3O2 solution with 71.0 mL of 0.109 M MgCl2 solution?
2 AgC2H3O2 (aq) + MgCl2 (aq) --> 2 AgCl (s) + Mg(C2H3O2)2 (aq)
You mean AgCl instead of NaCl.
Calculate moles AgC2H3O2. moles = M x L.
Do the same for MgCl2.
Look at how the moles combine and convert to moles AgCl. One of the reagent will be the limiting reagent unless you have stoichiometric amounts present. Then convert moles AgCl to grams. g = moles x molar mass.
To find the mass of NaCl formed, we need to calculate the number of moles of NaCl and then convert it to grams using its molar mass. Here are the steps to solve the problem:
1. Write down the balanced chemical equation:
2 AgC2H3O2 (aq) + MgCl2 (aq) --> 2 AgCl (s) + Mg(C2H3O2)2 (aq)
2. Determine the limiting reagent:
To do this, we need to compare the number of moles of each reactant to see which one will run out first. We will consider the moles of AgC2H3O2 and MgCl2 available in the initial solutions.
Given:
Volume of AgC2H3O2 solution = 54.0 mL
Concentration of AgC2H3O2 solution = 0.078 M
To find the number of moles of AgC2H3O2:
moles = concentration x volume (in liters)
moles AgC2H3O2 = 0.078 M x (54.0 mL / 1000 mL/L) = 0.004212 moles AgC2H3O2
Given:
Volume of MgCl2 solution = 71.0 mL
Concentration of MgCl2 solution = 0.109 M
To find the number of moles of MgCl2:
moles MgCl2 = 0.109 M x (71.0 mL / 1000 mL/L) = 0.007739 moles MgCl2
From the balanced equation, we can see that the stoichiometric ratio between AgC2H3O2 and NaCl is 2:2 or 1:1. However, the stoichiometric ratio between MgCl2 and NaCl is 1:2.
Comparing the moles of both reactants, we find that the moles of MgCl2 (0.007739 moles) are less than the moles of AgC2H3O2 (0.004212 moles). Therefore, MgCl2 is the limiting reagent.
3. Calculate the moles of NaCl formed:
Since the stoichiometric ratio between MgCl2 and NaCl is 1:2, the moles of NaCl formed will be twice the moles of MgCl2.
moles NaCl = 2 x moles MgCl2 = 2 x 0.007739 moles = 0.015478 moles NaCl
4. Convert moles to grams:
To convert moles of NaCl to grams, we need to multiply by the molar mass of NaCl.
The molar mass of NaCl is 58.44 g/mol.
mass NaCl = moles NaCl x molar mass NaCl = 0.015478 moles x 58.44 g/mol = 0.904 g
Therefore, approximately 0.904 grams of NaCl is formed from the given reaction.